python语言之字典dict简析
发布时间:2022-08-25 10:36:00 所属栏目:交互 来源:互联网
导读:1.基本的增删改查 def test_1(): # 增删改查 dict1 = {a: 1, b: 2} dict1[c] = 3 assert {a: 1, b: 2, c: 3} == dict1, dict 新增失败 del dict1[b] assert {a: 1, c: 3} == dict1, dict 删除失败 dict1[c] = 4 assert {a: 1, c: 4} == dict1, dict 修改失败
1.基本的增删改查 def test_1(): # 增删改查 dict1 = {'a': 1, 'b': 2} dict1['c'] = 3 assert {'a': 1, 'b': 2, 'c': 3} == dict1, 'dict 新增失败' del dict1['b'] assert {'a': 1, 'c': 3} == dict1, 'dict 删除失败' dict1['c'] = 4 assert {'a': 1, 'c': 4} == dict1, 'dict 修改失败' c = dict1['c'] assert 4 == c, 'dict 查询失败' pass 2. in和enumerate方法 def test_2(): # in, enumerate dict1 = {'a': 1, 'b': 2} indexs = [i for i, v in enumerate(dict1.items()) if v[0] == 'b'] assert [1] == indexs, 'dict enumerate error' assert 'a' in dict1, 'dict in error' pass 3.方法: setdefault,update,get,pop,popitem def test_3(): # setdefault,update,get,pop,popitem # setdefault 如果没有则增加,有则不变 dict1 = {'a': 1, 'b': 2} dict1.setdefault('c', 4) assert {'a': 1, 'b': 2, 'c': 4}, 'dict setdefault error' dict1.setdefault('b', 1) assert {'a': 1, 'b': 2, 'c': 4} == dict1, 'dict setdefault b error' dict1.update({'c': 5}) assert {'a': 1, 'b': 2, 'c': 5} == dict1, 'dict update error' c = dict1.get('c', 1) assert 5 == c, 'dict get error' f = dict1.get('f', 1) assert 1 == f, 'dict get f error' dict1.pop('c') assert {'a': 1, 'b': 2} == dict1, 'dict pop error' dict1.popitem() assert {'a': 1} == dict1, 'dict popitem error' pass 4. sort def test_4(): # sort dict1 = {'b': 2, 'a': 1} dict2 = dict(sorted(dict1.items(), key=lambda kv: kv[0])) assert {'a': 1, 'b': 2} == dict2, 'dict sorted 1 error' dict1 = {'b': 2, 'a': 1, 'c': 1} dict2 = dict(sorted(dict1.items(), key=lambda kv: (kv[1], kv[0]))) assert {'a': 1, 'c': 1, 'b': 2} pass 5.浅复制和深复制 import copy def test_5(): # 浅复制 和 深度复制 # 1.浅复制:不改变原字典 dict1 = {'a': 1, 'b': 2} dict2 = dict1.copy() dict2.update({'b': 1}) assert {'a': 1, 'b': 2} == dict1, 'dict copy 1 error' assert {'a': 1, 'b': 1} == dict2, 'dict copy 1.1 error' # 2.浅复制:改变原字典--子对象 dict1 = {'a': 1, 'b': {'c': 1}} dict2 = dict1.copy() dict2['b'].setdefault('d', 2) assert {'a': 1, 'b': {'c': 1, 'd': 2}} == dict1, 'dict copy 2 error' assert {'a': 1, 'b': {'c': 1, 'd': 2}} == dict2, 'dict copy 2.1 error' # 3.深复制:不改变原字典 dict1 = {'a': 1, 'b': {'c': 1}} dict2 = copy.deepcopy(dict1) dict2['b'].setdefault('d', 2) assert {'a': 1, 'b': {'c': 1}} == dict1, 'dict copy 3 error' assert {'a': 1, 'b': {'c': 1, 'd': 2}} == dict2, 'dict copy 3.1 error' pass 6.dict的各种初始化 def test_6(): # 方法:dict(p) dict1 = {} assert {} == dict1, 'dict new 1 error' dict1 = dict() assert {} == dict1, 'dict new 2 error' dict1 = dict({'a': 1}) assert {'a': 1} == dict1, 'dict new 3 error' dict1 = dict([('a', 1), ('b', 2)]) assert {'a': 1, 'b': 2} == dict1, 'dict new 4 error' dict1 = dict(a=1, b=2) assert {'a': 1, 'b': 2} == dict1, 'dict new 5 error' params = {'a': 1, 'b': 2} dict1 = dict(**params) assert {'a': 1, 'b': 2} == dict1, 'dict new 6 error' pass (编辑:咸宁站长网) 【声明】本站内容均来自网络,其相关言论仅代表作者个人观点,不代表本站立场。若无意侵犯到您的权利,请及时与联系站长删除相关内容! |